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Find the Standard Form of the Equation of the Hyperbola (0,±14)( 0 , \pm 14 )

Question 435

Multiple Choice

Find the standard form of the equation of the hyperbola with the given characteristics and center at the origin.
Vertices: (0,±14) ( 0 , \pm 14 ) ; asymptotes: y=±7xy = \pm 7 x


A) x2196+y24=1\frac { x ^ { 2 } } { 196 } + \frac { y ^ { 2 } } { 4 } = 1
B) y2196x24=1\frac { y ^ { 2 } } { 196 } - \frac { x ^ { 2 } } { 4 } = 1
C) y24+x2196=1\frac { y ^ { 2 } } { 4 } + \frac { x ^ { 2 } } { 196 } = 1
D) 196x244y2196=1\frac { 196 x ^ { 2 } } { 4 } - \frac { 4 y ^ { 2 } } { 196 } = 1
E) x24y2196=1\frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 196 } = 1

Correct Answer:

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