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The Vector V and Its Initial Point Are Given v=(92,12,8)\mathbf { v } = \left( \frac { 9 } { 2 } , - \frac { 1 } { 2 } , 8 \right)

Question 146

Multiple Choice

The vector v and its initial point are given.Find the terminal point. v=(92,12,8) \mathbf { v } = \left( \frac { 9 } { 2 } , - \frac { 1 } { 2 } , 8 \right)
Initial point: (7,6,12) \left( 7,6 , - \frac { 1 } { 2 } \right)


A) Terminal point is (232,112,152) \left( \frac { 23 } { 2 } , \frac { 11 } { 2 } , \frac { 15 } { 2 } \right) .
B) Terminal point is (232,152,112) \left( \frac { 23 } { 2 } , \frac { 15 } { 2 } , \frac { 11 } { 2 } \right) .
C) Terminal point is (112,232,152) \left( \frac { 11 } { 2 } , \frac { 23 } { 2 } , \frac { 15 } { 2 } \right) .
D) Terminal point is (112,152,232) \left( \frac { 11 } { 2 } , \frac { 15 } { 2 } , \frac { 23 } { 2 } \right) .
E) Terminal point is (152,112,232) \left( \frac { 15 } { 2 } , \frac { 11 } { 2 } , \frac { 23 } { 2 } \right) .

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