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Find the First Five Terms of the Sequence αn=n22n+1\alpha _ { n } = \frac { n ^ { 2 } } { 2 n + 1 }

Question 202

Multiple Choice

Find the first five terms of the sequence. αn=n22n+1\alpha _ { n } = \frac { n ^ { 2 } } { 2 n + 1 }


A) α1=13,α2=45,α3=97,α4=169,α5=115\alpha _ { 1 } = \frac { 1 } { 3 } , \alpha _ { 2 } = \frac { 4 } { 5 } , \alpha _ { 3 } = \frac { 9 } { 7 } , \alpha _ { 4 } = \frac { 16 } { 9 } , \alpha _ { 5 } = \frac { 11 } { 5 }
B) α1=3,α2=45,α3=79,α4=169,α5=2511\alpha _ { 1 } = 3 , \alpha _ { 2 } = \frac { 4 } { 5 } , \alpha _ { 3 } = \frac { 7 } { 9 } , \alpha _ { 4 } = \frac { 16 } { 9 } , \alpha _ { 5 } = \frac { 25 } { 11 }
C) α1=13,α2=45,α3=97,α4=169,α5=2511\alpha _ { 1 } = \frac { 1 } { 3 } , \alpha _ { 2 } = \frac { 4 } { 5 } , \alpha _ { 3 } = \frac { 9 } { 7 } , \alpha _ { 4 } = \frac { 16 } { 9 } , \alpha _ { 5 } = \frac { 25 } { 11 }
D) α1=3,α2=45,α3=73,α4=169,α5=2511\alpha _ { 1 } = 3 , \alpha _ { 2 } = \frac { 4 } { 5 } , \alpha _ { 3 } = \frac { 7 } { 3 } , \alpha _ { 4 } = \frac { 16 } { 9 } , \alpha _ { 5 } = \frac { 25 } { 11 }
E) α1=3,α2=45,α3=97,α4=169,α5=115\alpha _ { 1 } = 3 , \alpha _ { 2 } = \frac { 4 } { 5 } , \alpha _ { 3 } = \frac { 9 } { 7 } , \alpha _ { 4 } = \frac { 16 } { 9 } , \alpha _ { 5 } = \frac { 11 } { 5 }

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