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Find the Limit of the Sequence (If It Exists) αn=4n2+12n\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }

Question 191

Multiple Choice

Find the limit of the sequence (if it exists) . αn=4n2+12n\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }


A) limnαn=4\lim_ { n \rightarrow \infty } \alpha _ { n } = - 4
B) limnαn=12\lim _ { n \rightarrow \infty } \alpha _ { n } = \frac { 1 } { 2 }
C) limnαn=4\lim _ { n \rightarrow \infty }\alpha _ { n } = 4
D) limnαn=0\lim_ { n \rightarrow \infty } \alpha _ { n } = 0
E) limnan=\lim_ { n \rightarrow \infty } a _ { n } = \infty

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