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Ion Interaction Energies Are Determined by Coulomb's Law E=(2.31×1019Jnm)(Q1Q2d)E = \left( 2.31 \times 10 ^ { - 19 } J \cdot n m \right) \left( \frac { Q _ { 1 } Q _ { 2 } } { d } \right)

Question 94

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Ion interaction energies are determined by Coulomb's law: E=(2.31×1019Jnm) (Q1Q2d) E = \left( 2.31 \times 10 ^ { - 19 } J \cdot n m \right) \left( \frac { Q _ { 1 } Q _ { 2 } } { d } \right) Determine the energy of potassium chloride if the radius of the potassium ion is 133 pm and that of the chloride ion is 181 pm.


A) -7.36 * 10-19 J
B) -7.36 *10-22 J
C) 7.36 *10-19 J
D) 1.74 *10-18 J
E) -7.36 *10-25 J

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