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Find the Equation of the Line Tangent to the Graph x=1x = 1

Question 18

Essay

Find the equation of the line tangent to the graph of the given function at the point x=1x = 1 .
​ f(x)=(x2+2)(x3+x)f ( x ) = \left( x ^ { 2 } + 2 \right) \left( x ^ { 3 } + x \right)

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