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  2. Topic
    Mathematics
  3. Study Set
    Calculus Single and Multivariable
  4. Exam
    Exam 14: Differentiating Functions of Several Variables
  5. Question
    Find the Gradient of the Function\(f ( x , y ) = x ^ { 2 } y ^ { 3 }\)
Solved

Find the Gradient of the Function f(x,y)=x2y3f ( x , y ) = x ^ { 2 } y ^ { 3 }f(x,y)=x2y3

Question 3

Question 3

Short Answer

Find the gradient of the function f(x,y)=x2y3f ( x , y ) = x ^ { 2 } y ^ { 3 }f(x,y)=x2y3 at the point (1,1)( 1,1 )(1,1) and use the result to obtain a linear approximation for 1.0420.9831.04 ^ { 2 } 0.98 ^ { 3 }1.0420.983

Correct Answer:

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