Is the Taylor Polynomial of Degree 6 For $e^{-x^{2}}$ For X near 0 Given By

Short Answer

Is the Taylor polynomial of degree 6 for $e^{-x^{2}}$ for x near 0 given by $1+\frac{x^{2}}{2 !}+\frac{x^{4}}{4 !}+\frac{x^{6}}{6 !}$ ?