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Find the Taylor Series For $\sin x-\cos x$
A) $1+x-\frac{x^{2}}{2 !}-\frac{x^{3}}{3 !}+\frac{x^{4}}{4 !}+\frac{x^{5}}{5 !}-\cdots$

Question 20

Multiple Choice

Find the Taylor series for $\sin x-\cos x$ .

A) $1+x-\frac{x^{2}}{2 !}-\frac{x^{3}}{3 !}+\frac{x^{4}}{4 !}+\frac{x^{5}}{5 !}-\cdots$
B) $1-x-\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\frac{x^{4}}{4 !}-\frac{x^{5}}{5 !}-\cdots$
C) $-1+x+\frac{x^{2}}{2 !}-\frac{x^{3}}{3 !}-\frac{x^{4}}{4 !}+\frac{x^{5}}{5 !}+\ldots$
D) $-1-x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}-\frac{x^{4}}{4 !}-\frac{x^{5}}{5 !}+\ldots$

Find the Taylor Series For sin⁡x−cos⁡x\sin x-\cos xsinx−cosx A) 1+x−x22!−x33!+x44!+x55!−⋯1+x-\frac{x^{2}}{2 !}-\frac{x^{3}}{3 !}+\frac{x^{4}}{4 !}+\frac{x^{5}}{5 !}-\cdots1+x−2!x2​−3!x3​+4!x4​+5!x5​−⋯

Multiple Choice

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Find the Taylor Series For $\sin x-\cos x$
A) $1+x-\frac{x^{2}}{2 !}-\frac{x^{3}}{3 !}+\frac{x^{4}}{4 !}+\frac{x^{5}}{5 !}-\cdots$

Correct Answer:
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