Find$\int\left(\frac{1}{x+1}-\frac{1}{(x+1)^{2}}\right) d x$
A)$\ln |x+1|-\frac{3}{(x+1)^{3}}+C$ B)$\ln |x+1|+\frac{3}{(x+1)^{3}}+C$ C)$\ln |x+1|-\frac{1}{x+1}+C$

Question

Find$\int\left(\frac{1}{x+1}-\frac{1}{(x+1)^{2}}\right) d x$  
A)$\ln |x+1|-\frac{3}{(x+1)^{3}}+C$ B)$\ln |x+1|+\frac{3}{(x+1)^{3}}+C$ C)$\ln |x+1|-\frac{1}{x+1}+C$

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The Answer of Find$\int\left(\frac{1}{x+1}-\frac{1}{(x+1)^{2}}\right) d x$  
A)$\ln |x+1|-\frac{3}{(x+1)^{3}}+C$ B)$\ln |x+1|+\frac{3}{(x+1)^{3}}+C$ C)$\ln |x+1|-\frac{1}{x+1}+C$

Find $\int\left(\frac{1}{x+1}-\frac{1}{(x+1)^{2}}\right) d x$
A) $\ln |x+1|-\frac{3}{(x+1)^{3}}+C$ B) $\ln |x+1|+\frac{3}{(x+1)^{3}}+C$ C) $\ln |x+1|-\frac{1}{x+1}+C$

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