Solved

$\int t e^{a t} d t=\frac{1}{a} t e^{a t}-\frac{1}{a^{2}} e^{a t}+C$

Question 46

True/False

$\int t e^{a t} d t=\frac{1}{a} t e^{a t}-\frac{1}{a^{2}} e^{a t}+C$ , where a is a constant.

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