For $-2 \leq x \leq 2$ , Define $F(x)=\int_{-2}^{x} \sqrt{4-t^{2}} d t$

Short Answer

For $-2 \leq x \leq 2$ , define $F(x)=\int_{-2}^{x} \sqrt{4-t^{2}} d t$ .What is the value of $F(0)$ ? Round to 2 decimal places.