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At Time T = 0, a Bowling Ball Rolls Off h(t)=4.9t230t+250h(t)=-4.9 t^{2}-30 t+250

Question 86

Multiple Choice

At time t = 0, a bowling ball rolls off a 250-meter ledge with velocity 30 meters/sec downward.Express its height, h(t) , in meters above the ground as a function of time, t, in seconds.


A) h(t) =4.9t230t+250h(t) =-4.9 t^{2}-30 t+250
B) h(t) =4.9t230t250h(t) =-4.9 t^{2}-30 t-250
C) h(t) =4.9t230t+250h(t) =4.9 t^{2}-30 t+250
D) h(t) =4.9t230t250h(t) =4.9 t^{2}-30 t-250

Correct Answer:

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