Rewrite the Equation in Standard Form $$x ^ { 2 } + y ^ { 2 } - 12 y + 20 = 0$$

Multiple Choice

Rewrite the equation in standard form. Find the center and radius of the circle.
- $$x ^ { 2 } + y ^ { 2 } - 12 y + 20 = 0$$

A) $x ^ { 2 } + ( y + 6 ) ^ { 2 } = 16$
center $( 0 , - 6 ) , \mathrm { r } = 4$
B) $x ^ { 2 } + ( y - 6 ) ^ { 2 } = 16$
center $( 0,6 ) , \mathrm { r } = 4$
C) $( x - 6 ) ^ { 2 } + y ^ { 2 } = 16$
center $( 6,0 ) , \mathrm { r } = 4$
D) $x ^ { 2 } + ( y - 6 ) ^ { 2 } = 16$
center $( 0 , - 6 ) , \mathrm { r } = 4$