Rewrite the Equation in Standard Form $$x ^ { 2 } + y ^ { 2 } + 14 y + 40 = 0$$

Multiple Choice

Rewrite the equation in standard form. Find the center and radius of the circle.
- $$x ^ { 2 } + y ^ { 2 } + 14 y + 40 = 0$$

A) $( x + 7 ) ^ { 2 } + y ^ { 2 } = 9$
center $( - 7,0 ) , \mathrm { r } = 3$
B) $x ^ { 2 } + ( y + 7 ) ^ { 2 } = 9$
center $( 0 , - 7 ) , r = 3$
C) $x ^ { 2 } + ( y - 7 ) ^ { 2 } = 9$
center $( 0,7 ) , \mathrm { r } = 3$
D) $x ^ { 2 } + ( y + 7 ) ^ { 2 } = 9$
center $( 0,7 ) , r = 3$