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Determine If the Vector P Is in Span S or Aff

Question 47

Multiple Choice

Determine if the vector p is in Span S or aff S.
-Let v1=[2132],v2=[3104],v3=[5412],p=[2372]\mathbf { v } _ { 1 } = \left[ \begin{array} { r } 2 \\ 1 \\ 3 \\ - 2 \end{array} \right] , \mathbf { v } _ { 2 } = \left[ \begin{array} { r } 3 \\ - 1 \\ 0 \\ 4 \end{array} \right] , \mathbf { v } _ { 3 } = \left[ \begin{array} { r } 5 \\ 4 \\ - 1 \\ - 2 \end{array} \right] , \mathbf { p } = \left[ \begin{array} { r } 2 \\ - 3 \\ 7 \\ 2 \end{array} \right] , and S={v1,v2,v3}\mathrm { S } = \left\{ \mathbf { v } _ { 1 } , \mathbf { v } _ { 2 } , \mathbf { v } _ { 3 } \right\} . It can be shown that SS is linearly independent.


A) p\mathbf { p } \in span SS and p\mathbf { p } \in aff SS
B) pspanS\mathbf { p } \notin \operatorname { span } S and p\mathbf { p } \in aff SS
C) p\mathbf { p } \notin span SS and p\mathbf { p } \notin aff SS
D) p\mathbf { p } \in span SS and p\mathbf { p } \notin aff SS

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