Solve the Problem A) B) $$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 }\end{array} \right] = \left[ \begin{array} { r } - 3 \\3 \\1\end{array} \right]$$

Multiple Choice

Solve the problem.
-Find the general solution of the homogeneous system below. Give your answer as a vector. $$\begin{array} { r } x _ { 1 } + 2 x _ { 2 } - 3 x _ { 3 } = 0 \\4 x _ { 1 } + 7 x _ { 2 } - 9 x _ { 3 } = 0 \\- x _ { 1 } - 4 x _ { 2 } + 9 x _ { 3 } = 0\end{array}$$

A)
$$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 }\end{array} \right] = x _ { 3 } \left[ \begin{array} { r } 3 \\- 3 \\1\end{array} \right]$$
B)
$$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 }\end{array} \right] = \left[ \begin{array} { r } - 3 \\3 \\1\end{array} \right]$$
C)
$$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 }\end{array} \right] = x _ { 3 } \left[ \begin{array} { r } - 3 \\3 \\1\end{array} \right]$$
D)
$$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 }\end{array} \right] = x _ { 3 } \left[ \begin{array} { r } - 3 \\3 \\0\end{array} \right]$$