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    Exam 5: Analytic Trigonometry
  5. Question
    Find All Solutions of the Equation\(2 \sin ^{2} x+3 \sin x-2=0\)
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Find All Solutions of the Equation 2sin⁡2x+3sin⁡x−2=02 \sin ^{2} x+3 \sin x-2=02sin2x+3sinx−2=0

Question 1

Question 1

Short Answer

Find all solutions of the equation 2sin⁡2x+3sin⁡x−2=02 \sin ^{2} x+3 \sin x-2=02sin2x+3sinx−2=0 on the interval [0,2π)[0,2 \pi)[0,2π) (Your answer should be exact.)

Correct Answer:

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