Solve
-A Rocket Is Launched from the Top of a Cliff

Multiple Choice

Solve.
-A rocket is launched from the top of a cliff that is 48 feet high with an initial velocity of 120 feet per second. The height, $h$ , of the rocket after $t$ seconds is given by the equation $h = - 16 t ^ { 2 } + 120 t + 48$ . How long after the rocket is launched will it strike the ground? Round to the nearest tenth of a second, if necessary.

A) $9.1 \mathrm { sec }$
B) $8.5 \mathrm { sec }$
C) $7.9 \mathrm { sec }$
D) $9.5 \mathrm { sec }$