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The Graph of the Equation Is a Circle $x^{2}+y^{2}=36$ A) Center $( 0,0 )$

Question 92

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x^{2}+y^{2}=36$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}=36 A) center ( 0,0 ) ; radius = 6 B) center ( 0,0 ) ; radius = \sqrt { 6 }$

A) center $( 0,0 )$ ; radius $= 6$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}=36 A) center ( 0,0 ) ; radius = 6 B) center ( 0,0 ) ; radius = \sqrt { 6 }$

B) center $( 0,0 ) ;$ radius $= \sqrt { 6 }$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}=36 A) center ( 0,0 ) ; radius = 6 B) center ( 0,0 ) ; radius = \sqrt { 6 }$

The Graph of the Equation Is a Circle x2+y2=36x^{2}+y^{2}=36x2+y2=36 A) Center (0,0)( 0,0 )(0,0)

Multiple Choice

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The Graph of the Equation Is a Circle $x^{2}+y^{2}=36$ A) Center $( 0,0 )$

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