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The Graph of the Equation Is a Circle $(x+4)^{2}+(y+1)^{2}=16$ A) Center $( 4 , - 1 )$

Question 95

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $(x+4) ^{2}+(y+1) ^{2}=16$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x+4) ^{2}+(y+1) ^{2}=16 A) center ( 4 , - 1 ) ; radius = 4 B) center ( - 4,1 ) ; radius = 4 C) center ( 4,1 ) ; radius = 4 D) center ( - 4 , - 1 ) ; radius = 4$

A) center $( 4 , - 1 )$ ; radius $= 4$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x+4) ^{2}+(y+1) ^{2}=16 A) center ( 4 , - 1 ) ; radius = 4 B) center ( - 4,1 ) ; radius = 4 C) center ( 4,1 ) ; radius = 4 D) center ( - 4 , - 1 ) ; radius = 4$
B) center $( - 4,1 )$ ; radius $= 4$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x+4) ^{2}+(y+1) ^{2}=16 A) center ( 4 , - 1 ) ; radius = 4 B) center ( - 4,1 ) ; radius = 4 C) center ( 4,1 ) ; radius = 4 D) center ( - 4 , - 1 ) ; radius = 4$
C) center $( 4,1 )$ ; radius $= 4$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x+4) ^{2}+(y+1) ^{2}=16 A) center ( 4 , - 1 ) ; radius = 4 B) center ( - 4,1 ) ; radius = 4 C) center ( 4,1 ) ; radius = 4 D) center ( - 4 , - 1 ) ; radius = 4$
D) center $( - 4 , - 1 )$ ; radius $= 4$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - (x+4) ^{2}+(y+1) ^{2}=16 A) center ( 4 , - 1 ) ; radius = 4 B) center ( - 4,1 ) ; radius = 4 C) center ( 4,1 ) ; radius = 4 D) center ( - 4 , - 1 ) ; radius = 4$

The Graph of the Equation Is a Circle (x+4)2+(y+1)2=16(x+4)^{2}+(y+1)^{2}=16(x+4)2+(y+1)2=16 A) Center (4,−1)( 4 , - 1 )(4,−1)

Multiple Choice

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The Graph of the Equation Is a Circle $(x+4)^{2}+(y+1)^{2}=16$ A) Center $( 4 , - 1 )$

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