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The Graph of the Equation Is a Circle $x^{2}+y^{2}-4 x-2 y-11=0$

Question 55

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x^{2}+y^{2}-4 x-2 y-11=0$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}-4 x-2 y-11=0 A) center ( 2 , - 1 ) ; radius = 4 B) center ( 2,1 ) ; radius = 4 C) center ( - 2 , - 1 ) ; radius = 4 D) center ( - 2,1 ) ; radius = 4$

A) center $( 2 , - 1 )$ ; radius $= 4$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}-4 x-2 y-11=0 A) center ( 2 , - 1 ) ; radius = 4 B) center ( 2,1 ) ; radius = 4 C) center ( - 2 , - 1 ) ; radius = 4 D) center ( - 2,1 ) ; radius = 4$
B) center $( 2,1 )$ ; radius $= 4$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}-4 x-2 y-11=0 A) center ( 2 , - 1 ) ; radius = 4 B) center ( 2,1 ) ; radius = 4 C) center ( - 2 , - 1 ) ; radius = 4 D) center ( - 2,1 ) ; radius = 4$
C) center $( - 2 , - 1 )$ ; radius $= 4$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}-4 x-2 y-11=0 A) center ( 2 , - 1 ) ; radius = 4 B) center ( 2,1 ) ; radius = 4 C) center ( - 2 , - 1 ) ; radius = 4 D) center ( - 2,1 ) ; radius = 4$
D) center $( - 2,1 )$ ; radius $= 4$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}-4 x-2 y-11=0 A) center ( 2 , - 1 ) ; radius = 4 B) center ( 2,1 ) ; radius = 4 C) center ( - 2 , - 1 ) ; radius = 4 D) center ( - 2,1 ) ; radius = 4$

The Graph of the Equation Is a Circle x2+y2−4x−2y−11=0x^{2}+y^{2}-4 x-2 y-11=0x2+y2−4x−2y−11=0

Multiple Choice

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The Graph of the Equation Is a Circle $x^{2}+y^{2}-4 x-2 y-11=0$

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