Solved

The Graph of the Equation Is a Circle $x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9$

Question 60

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9 A) center ( - 4,0 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( 4,0 ) ; radius = 3 D) center ( 0 , - 4 ) ; radius = 3$

A) center $( - 4,0 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9 A) center ( - 4,0 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( 4,0 ) ; radius = 3 D) center ( 0 , - 4 ) ; radius = 3$
B) center $( 0,4 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9 A) center ( - 4,0 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( 4,0 ) ; radius = 3 D) center ( 0 , - 4 ) ; radius = 3$
C) center $( 4,0 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9 A) center ( - 4,0 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( 4,0 ) ; radius = 3 D) center ( 0 , - 4 ) ; radius = 3$
D) center $( 0 , - 4 )$ ; radius $= 3$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9 A) center ( - 4,0 ) ; radius = 3 B) center ( 0,4 ) ; radius = 3 C) center ( 4,0 ) ; radius = 3 D) center ( 0 , - 4 ) ; radius = 3$

The Graph of the Equation Is a Circle x2+(y+4)2=9x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9x2+(y+4)2=9

Multiple Choice

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The Graph of the Equation Is a Circle $x ^ { 2 } + ( y + 4 ) ^ { 2 } = 9$

Correct Answer:
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