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The Graph of the Equation Is a Circle $x^{2}+2 x+y^{2}-4 y-19=0$

Question 64

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x^{2}+2 x+y^{2}-4 y-19=0$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+2 x+y^{2}-4 y-19=0 A) center ( 1,2 ) ; radius = 2 \sqrt { 6 } B) center ( 1 , - 2 ) ; radius = 2 \sqrt { 6 } C) center ( - 1,2 ) ; radius = 2 \sqrt { 6 } D) center ( - 1,2 ) ; radius = 24$

A) center $( 1,2 ) ;$ radius $= 2 \sqrt { 6 }$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+2 x+y^{2}-4 y-19=0 A) center ( 1,2 ) ; radius = 2 \sqrt { 6 } B) center ( 1 , - 2 ) ; radius = 2 \sqrt { 6 } C) center ( - 1,2 ) ; radius = 2 \sqrt { 6 } D) center ( - 1,2 ) ; radius = 24$
B) center $( 1 , - 2 )$ ; radius $= 2 \sqrt { 6 }$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+2 x+y^{2}-4 y-19=0 A) center ( 1,2 ) ; radius = 2 \sqrt { 6 } B) center ( 1 , - 2 ) ; radius = 2 \sqrt { 6 } C) center ( - 1,2 ) ; radius = 2 \sqrt { 6 } D) center ( - 1,2 ) ; radius = 24$
C) center $( - 1,2 )$ ; radius $= 2 \sqrt { 6 }$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+2 x+y^{2}-4 y-19=0 A) center ( 1,2 ) ; radius = 2 \sqrt { 6 } B) center ( 1 , - 2 ) ; radius = 2 \sqrt { 6 } C) center ( - 1,2 ) ; radius = 2 \sqrt { 6 } D) center ( - 1,2 ) ; radius = 24$
D) center $( - 1,2 )$ ; radius $= 24$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+2 x+y^{2}-4 y-19=0 A) center ( 1,2 ) ; radius = 2 \sqrt { 6 } B) center ( 1 , - 2 ) ; radius = 2 \sqrt { 6 } C) center ( - 1,2 ) ; radius = 2 \sqrt { 6 } D) center ( - 1,2 ) ; radius = 24$

The Graph of the Equation Is a Circle x2+2x+y2−4y−19=0x^{2}+2 x+y^{2}-4 y-19=0x2+2x+y2−4y−19=0

Multiple Choice

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The Graph of the Equation Is a Circle $x^{2}+2 x+y^{2}-4 y-19=0$

Correct Answer:
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