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L Let YY Be a Bernoulli Random Variable with Success Probability Pr(Y=1)=p\operatorname { Pr } ( Y = 1 ) = p

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L Let YY be a Bernoulli random variable with success probability Pr(Y=1)=p\operatorname { Pr } ( Y = 1 ) = p , and let Y1,,YnY _ { 1 } , \ldots , Y _ { n } be i.i.d. draws from this distribution. Let p^\hat { p } be the fraction of successes (1s) in this sample. Given the following statement
Pr(1.96<z<1.96)=0.95\operatorname { Pr } ( - 1.96 < z < 1.96 ) = 0.95
and assuming that p^\hat { p } being approximately distributed N(p,p(1p)n)N \left( p , \frac { p ( 1 - p ) } { n } \right) , derive the 95%95 \% confidence interval for pp by solving the above inequalities.

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