Solved

Find the Standard Form of the Equation of the Ellipse (x+1)216+(y1)24=1\frac { ( x + 1 ) ^ { 2 } } { 16 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1

Question 101

Multiple Choice

Find the standard form of the equation of the ellipse or hyperbola shown.
- Find the standard form of the equation of the ellipse or hyperbola shown. -   A)   \frac { ( x + 1 )  ^ { 2 } } { 16 } + \frac { ( y - 1 )  ^ { 2 } } { 4 } = 1  B)   \frac { ( x + 1 )  ^ { 2 } } { 16 } - \frac { ( y - 1 )  ^ { 2 } } { 4 } = 1  C)   \frac { ( x + 1 )  ^ { 2 } } { 4 } - \frac { ( y - 1 )  ^ { 2 } } { 2 } = 1  D)   \frac { ( x - 1 )  ^ { 2 } } { 16 } - \frac { ( y + 1 )  ^ { 2 } } { 4 } = 1


A) (x+1) 216+(y1) 24=1\frac { ( x + 1 ) ^ { 2 } } { 16 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1
B) (x+1) 216(y1) 24=1\frac { ( x + 1 ) ^ { 2 } } { 16 } - \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1
C) (x+1) 24(y1) 22=1\frac { ( x + 1 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 2 } = 1
D) (x1) 216(y+1) 24=1\frac { ( x - 1 ) ^ { 2 } } { 16 } - \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions