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Let F Be a One-To-One Function and Let G Be (fg)(x)=( f \circ g ) ( x ) =

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Let f be a one-to-one function and let g be the inverse of f. Then (fg)(x)=( f \circ g ) ( x ) = ________and (gf)(x)=\left( g \circ f ^ { \prime } \right) ( x ) = ________ .

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