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Solve the Equation log2x+3+log2x=1\log _ { 2 } \sqrt { x + 3 } + \log _ { 2 } \sqrt { x } = 1

Question 7

Multiple Choice

Solve the equation.
- log2x+3+log2x=1\log _ { 2 } \sqrt { x + 3 } + \log _ { 2 } \sqrt { x } = 1


A) {4,1}\{ - 4,1 \}
B) { }
C) {4}\{ - 4 \}
D) {1}\{ 1 \}

Correct Answer:

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