Given P Is True, Q Is True, and R Is$$\sim [ ( \sim \mathrm { q } - \mathrm { r } ) \leftrightarrow ( \mathrm { q } \vee \mathrm { r } ) ]$$

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Given P Is True, Q Is True, and R Is$$\sim [ ( \sim \mathrm { q } - \mathrm { r } )  \leftrightarrow ( \mathrm { q } \vee \mathrm { r } ) ]$$

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The Answer of Given P Is True, Q Is True, and R Is$$\sim [ ( \sim \mathrm { q } - \mathrm { r } )  \leftrightarrow ( \mathrm { q } \vee \mathrm { r } ) ]$$

Given P Is True, Q Is True, and R Is $\sim [ ( \sim \mathrm { q } - \mathrm { r } ) \leftrightarrow ( \mathrm { q } \vee \mathrm { r } ) ]$

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Given P Is True, Q Is True, and R Is ∼[(∼q−r)↔(q∨r)]\sim [ ( \sim \mathrm { q } - \mathrm { r } ) \leftrightarrow ( \mathrm { q } \vee \mathrm { r } ) ]∼[(∼q−r)↔(q∨r)]

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Given P Is True, Q Is True, and R Is $\sim [ ( \sim \mathrm { q } - \mathrm { r } ) \leftrightarrow ( \mathrm { q } \vee \mathrm { r } ) ]$

Correct Answer:
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