Solve the problem.

-Suppose that a hair dryer operates on a voltage that can be represented by the relation

V ( t ) = 160 \cos ( 120 \pi t )

and that it draws a current represented by the relation

I ( t ) = 12 \cos ( 120 \pi t )

, where

t

is time measured in seconds. The power consumed by the appliance is P =VI. Graph th power in [0, 0.04, 0.01] by

[ - 200,2000,200 ]

and use an identity to write the expression for the power in the form

\mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } ) + \mathrm { d }

, where

\mathrm { a } , \mathrm { k }

, and

\mathrm { d }

are constants.
A)

\mathrm { P } = 960 \cos ( 240 \pi \mathrm { t } ) + 960

[ 0,0.04,0.01 ]

[ - 200,2000,200 ]

$Solve the problem. -Suppose that a hair dryer operates on a voltage that can be represented by the relation V ( t ) = 160 \cos ( 120 \pi t ) and that it draws a current represented by the relation I ( t ) = 12 \cos ( 120 \pi t ) , where t is time measured in seconds. The power consumed by the appliance is P =VI. Graph th power in [0, 0.04, 0.01] by [ - 200,2000,200 ] and use an identity to write the expression for the power in the form \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } ) + \mathrm { d } , where \mathrm { a } , \mathrm { k } , and \mathrm { d } are constants. A) \mathrm { P } = 960 \cos ( 240 \pi \mathrm { t } ) + 960 [ 0,0.04,0.01 ] by [ - 200,2000,200 ] B) \mathrm { P } = 1920 \cos ( 240 \pi \mathrm { t } ) + 1920 [ 0,0.04,0.01 ] by [ - 200,2000,200 ] C) P = 960 \cos ( 120 \pi t ) + 960 [ 0,0.04,0.01 ] by [ - 200,2000,200 ] D) P = - 960 \cos ( 240 \pi t ) + 960 [ 0,0.04,0.01 ] by [ - 200,2000,200 ]$

B)