Solved

Solve the Problem V(t)=160cos(120πt)V ( t ) = 160 \cos ( 120 \pi t )

Question 52

Multiple Choice

Solve the problem.

-Suppose that a hair dryer operates on a voltage that can be represented by the relation V(t) =160cos(120πt) V ( t ) = 160 \cos ( 120 \pi t ) and that it draws a current represented by the relation I(t) =12cos(120πt) I ( t ) = 12 \cos ( 120 \pi t ) , where tt is time measured in seconds. The power consumed by the appliance is P =VI. Graph th power in [0, 0.04, 0.01] by [200,2000,200][ - 200,2000,200 ] and use an identity to write the expression for the power in the form P=acos(kπt) +d\mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } ) + \mathrm { d } , where a,k\mathrm { a } , \mathrm { k } , and d\mathrm { d } are constants.


A) P=960cos(240πt) +960\mathrm { P } = 960 \cos ( 240 \pi \mathrm { t } ) + 960
[0,0.04,0.01][ 0,0.04,0.01 ] by [200,2000,200][ - 200,2000,200 ]
 Solve the problem.  -Suppose that a hair dryer operates on a voltage that can be represented by the relation  V ( t )  = 160 \cos ( 120 \pi t )   and that it draws a current represented by the relation  I ( t )  = 12 \cos ( 120 \pi t )  , where  t  is time measured in seconds. The power consumed by the appliance is P =VI. Graph th power in [0, 0.04, 0.01] by  [ - 200,2000,200 ]  and use an identity to write the expression for the power in the form  \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } )  + \mathrm { d } , where  \mathrm { a } , \mathrm { k } , and  \mathrm { d }  are constants. A)   \mathrm { P } = 960 \cos ( 240 \pi \mathrm { t } )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]      B)   \mathrm { P } = 1920 \cos ( 240 \pi \mathrm { t } )  + 1920   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]    C)   P = 960 \cos ( 120 \pi t )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     D)   P = - 960 \cos ( 240 \pi t )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]


B) P=1920cos(240πt) +1920\mathrm { P } = 1920 \cos ( 240 \pi \mathrm { t } ) + 1920
[0,0.04,0.01][ 0,0.04,0.01 ] by [200,2000,200][ - 200,2000,200 ]
 Solve the problem.  -Suppose that a hair dryer operates on a voltage that can be represented by the relation  V ( t )  = 160 \cos ( 120 \pi t )   and that it draws a current represented by the relation  I ( t )  = 12 \cos ( 120 \pi t )  , where  t  is time measured in seconds. The power consumed by the appliance is P =VI. Graph th power in [0, 0.04, 0.01] by  [ - 200,2000,200 ]  and use an identity to write the expression for the power in the form  \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } )  + \mathrm { d } , where  \mathrm { a } , \mathrm { k } , and  \mathrm { d }  are constants. A)   \mathrm { P } = 960 \cos ( 240 \pi \mathrm { t } )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]      B)   \mathrm { P } = 1920 \cos ( 240 \pi \mathrm { t } )  + 1920   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]    C)   P = 960 \cos ( 120 \pi t )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     D)   P = - 960 \cos ( 240 \pi t )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]
C) P=960cos(120πt) +960P = 960 \cos ( 120 \pi t ) + 960
[0,0.04,0.01][ 0,0.04,0.01 ] by [200,2000,200][ - 200,2000,200 ]
 Solve the problem.  -Suppose that a hair dryer operates on a voltage that can be represented by the relation  V ( t )  = 160 \cos ( 120 \pi t )   and that it draws a current represented by the relation  I ( t )  = 12 \cos ( 120 \pi t )  , where  t  is time measured in seconds. The power consumed by the appliance is P =VI. Graph th power in [0, 0.04, 0.01] by  [ - 200,2000,200 ]  and use an identity to write the expression for the power in the form  \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } )  + \mathrm { d } , where  \mathrm { a } , \mathrm { k } , and  \mathrm { d }  are constants. A)   \mathrm { P } = 960 \cos ( 240 \pi \mathrm { t } )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]      B)   \mathrm { P } = 1920 \cos ( 240 \pi \mathrm { t } )  + 1920   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]    C)   P = 960 \cos ( 120 \pi t )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     D)   P = - 960 \cos ( 240 \pi t )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]

D) P=960cos(240πt) +960P = - 960 \cos ( 240 \pi t ) + 960
[0,0.04,0.01][ 0,0.04,0.01 ] by [200,2000,200][ - 200,2000,200 ]
 Solve the problem.  -Suppose that a hair dryer operates on a voltage that can be represented by the relation  V ( t )  = 160 \cos ( 120 \pi t )   and that it draws a current represented by the relation  I ( t )  = 12 \cos ( 120 \pi t )  , where  t  is time measured in seconds. The power consumed by the appliance is P =VI. Graph th power in [0, 0.04, 0.01] by  [ - 200,2000,200 ]  and use an identity to write the expression for the power in the form  \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } )  + \mathrm { d } , where  \mathrm { a } , \mathrm { k } , and  \mathrm { d }  are constants. A)   \mathrm { P } = 960 \cos ( 240 \pi \mathrm { t } )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]      B)   \mathrm { P } = 1920 \cos ( 240 \pi \mathrm { t } )  + 1920   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]    C)   P = 960 \cos ( 120 \pi t )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     D)   P = - 960 \cos ( 240 \pi t )  + 960   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions