Give a rule for the piecewise-defined function. Then give the domain and range.
- $Give a rule for the piecewise-defined function. Then give the domain and range. - A) f ( x ) = \left\{ \begin{array} { c l } - 5 & \text { if } x \leq - 2 \\ 3 & \text { if } x > 1 \end{array} \right. ; Domain: \{ - 5,3 \} , Range: ( \infty - 2 ] \cup ( 1 , \infty ) B) f ( x ) = \left\{ \begin{array} { c l } - 5 & \text { if } x < - 2 \\ 3 & \text { if } x \geq 1 \end{array} \right. ; Domain: ( \infty - 2 ) \cup [ 1 , \infty ) , Range: \{ - 5,3 \} C) f ( x ) = \left\{ \begin{array} { c l } - 5 & \text { if } x \leq - 2 \\ 3 & \text { if } x > 1 \end{array} \right. ; Domain: ( \infty - 2 ] \cup ( 1 , \infty ) , Range: \{ - 5,3 \} D) f ( x ) = \left\{ \begin{array} { c l } - 5 & \text { if } x < - 2 \\ 3 & \text { if } x \geq 1 \end{array} \right. ; Domain: \{ - 5,3 \} , Range: ( \infty - 2 ) \cup [ 1 , \infty )$
A)

f ( x ) = \left\{ \begin{array} { c l } - 5 & \text { if } x \leq - 2 \\ 3 & \text { if } x > 1 \end{array} \right.

; Domain:

\{ - 5,3 \}

, Range:

( \infty - 2 ] \cup ( 1 , \infty )

f ( x ) = \left\{ \begin{array} { c l } - 5 & \text { if } x < - 2 \\ 3 & \text { if } x \geq 1 \end{array} \right.

; Domain:

( \infty - 2 ) \cup [ 1 , \infty )

, Range:

\{ - 5,3 \}

f ( x ) = \left\{ \begin{array} { c l } - 5 & \text { if } x \leq - 2 \\ 3 & \text { if } x > 1 \end{array} \right.

; Domain:

( \infty - 2 ] \cup ( 1 , \infty )

, Range:

\{ - 5,3 \}

f ( x ) = \left\{ \begin{array} { c l } - 5 & \text { if } x < - 2 \\ 3 & \text { if } x \geq 1 \end{array} \right.

; Domain:

\{ - 5,3 \}

, Range:

( \infty - 2 ) \cup [ 1 , \infty )

Graph the Function f(x)=16∣−x∣f(x)=\frac{1}{6}|-x|f(x)=61​∣−x∣ A) B) C) D)

Multiple Choice

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Graph the Function $f(x)=\frac{1}{6}|-x|$ A)

B)

C)

D)

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