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    Precalculus Study Set 3
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    Exam 11: Analytic Geometry
  5. Question
    Graph the Hyperbola\[\frac { y ^ { 2 } } { 9 } - \frac { x ^ { 2 } } { 36 } = 1\]
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Graph the Hyperbola y29−x236=1\frac { y ^ { 2 } } { 9 } - \frac { x ^ { 2 } } { 36 } = 19y2​−36x2​=1

Question 50

Question 50

Multiple Choice

Graph the hyperbola.
- y29−x236=1\frac { y ^ { 2 } } { 9 } - \frac { x ^ { 2 } } { 36 } = 19y2​−36x2​=1
 Graph the hyperbola. - \frac { y ^ { 2 } } { 9 } - \frac { x ^ { 2 } } { 36 } = 1     A)     B)    C)     D)


A)
 Graph the hyperbola. - \frac { y ^ { 2 } } { 9 } - \frac { x ^ { 2 } } { 36 } = 1     A)     B)    C)     D)

B)
 Graph the hyperbola. - \frac { y ^ { 2 } } { 9 } - \frac { x ^ { 2 } } { 36 } = 1     A)     B)    C)     D)
C)
 Graph the hyperbola. - \frac { y ^ { 2 } } { 9 } - \frac { x ^ { 2 } } { 36 } = 1     A)     B)    C)     D)

D)
 Graph the hyperbola. - \frac { y ^ { 2 } } { 9 } - \frac { x ^ { 2 } } { 36 } = 1     A)     B)    C)     D)

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