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Transform the Polar Equation to an Equation in Rectangular Coordinates $\theta=\frac{\pi}{3}$

Question 44

Multiple Choice

Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation.
- $\theta=\frac{\pi}{3}$
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta=\frac{\pi}{3} A) B) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{\pi} with the polar axis D) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} \text {; circle, radius } \frac{\pi}{3} \text {, } center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$

A)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta=\frac{\pi}{3} A) B) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{\pi} with the polar axis D) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} \text {; circle, radius } \frac{\pi}{3} \text {, } center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$

B)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta=\frac{\pi}{3} A) B) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{\pi} with the polar axis D) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} \text {; circle, radius } \frac{\pi}{3} \text {, } center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$

$y=\sqrt{3} x$ ; line through the pole making an angle of $\frac{\pi}{3}$ with the polar axis

C)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta=\frac{\pi}{3} A) B) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{\pi} with the polar axis D) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} \text {; circle, radius } \frac{\pi}{3} \text {, } center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$

$y=-\frac{\sqrt{3}}{3} x$ ; line through the pole making an angle of $\frac{\pi}{\pi}$ with the polar axis
D)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta=\frac{\pi}{3} A) B) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{\pi} with the polar axis D) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} \text {; circle, radius } \frac{\pi}{3} \text {, } center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$
$y=-\frac{\pi}{3} ;$ horizontal line $\frac{\pi}{3}$ units below the pole

$\left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} \text {; circle, radius } \frac{\pi}{3} \text {, }$
center at $\left(\frac{\pi}{3}, 0\right)$ in rectangular coordinates

Transform the Polar Equation to an Equation in Rectangular Coordinates θ=π3\theta=\frac{\pi}{3}θ=3π​

Multiple Choice

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Transform the Polar Equation to an Equation in Rectangular Coordinates $\theta=\frac{\pi}{3}$

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