Determine i) the domain of the function, ii) the range of the function, iii) the domain of the inverse, and iv) the range of
the inverse.
-

f ( x ) = \sqrt { 5 x + 4 }

f(x): D=\left\{x \mid x \geq-\frac{4}{5}\right\}, R=\{y \mid y \geq 0\}

f^{-1}(x): D

is all real numbers,

R=\left\{y \mid y \geq-\frac{4}{5}\right\}

f ( x ) : D = \left\{ x \mid x \geq - \frac { 4 } { 5 } \right\} , R = \{ y \mid y \geq 0 \}

;

\mathrm { f } ^ { - 1 } ( \mathrm { x } )

\mathrm { D }

is all real numbers,

\mathrm { R } = \left\{ \mathrm { y } \mid \mathrm { y } \geq - \frac { 4 } { 5 } \right\}

\mathrm { f } - 1 ( \mathrm { x } ) : \mathrm { D } = \left\{ \mathrm { x } | \mathrm { x } \geq 0 \rangle , \mathrm { R } = \left\{ \mathrm { y } \mid \mathrm { y } \geq - \frac { 4 } { 5 } \right\} \right.

f ( x ) : D = \left\{ x \mid x \geq - \frac { 4 } { 5 } \right\} , R

is all real numbers;

f^{-1}(x): D \text { is all real numbers, } R=\left\{y \mid y \geq-\frac{4}{5}\right\}

\begin{array}{l}f(x): D=\{x \mid x \geq 0\}, R=\{y \mid y \geq 0\} \\f^{-1}(x): D=\{x \mid x \geq 0\}, R=\left\{y \mid y \geq-\frac{4}{5}\right\}\end{array}

For the Given Functions F and G, Find the Requested f(x)=5x−1,g(x)=16x;f ( x ) = \frac { 5 } { x - 1 } , \quad g ( x ) = \frac { 1 } { 6 x } ; \quadf(x)=x−15​,g(x)=6x1​;

Multiple Choice