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Solve the System Using the Inverse Method {x+2y+3z=10x+y+z=2x2z=1\left\{ \begin{array} { l } x + 2 y + 3 z = 10 \\x + y + z = 2 \\x - 2 z = - 1\end{array} \right.

Question 131

Multiple Choice

Solve the system using the inverse method.
- {x+2y+3z=10x+y+z=2x2z=1\left\{ \begin{array} { l } x + 2 y + 3 z = 10 \\x + y + z = 2 \\x - 2 z = - 1\end{array} \right.


A) x=11,y=18,z=5x = - 11 , y = 18 , z = - 5
B) x=27,y=38,z=13x = 27 , y = 38 , z = 13
C) x=10,y=0,z=0x = 10 , y = 0 , z = 0
D) x=13,y=28,z=5x = - 13 , y = 28 , z = - 5

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