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Convert the Equation to the Standard Form for a Hyperbola y24x24y16x16=0y ^ { 2 } - 4 x ^ { 2 } - 4 y - 16 x - 16 = 0

Question 69

Multiple Choice

Convert the equation to the standard form for a hyperbola by completing the square on x and y.
- y24x24y16x16=0y ^ { 2 } - 4 x ^ { 2 } - 4 y - 16 x - 16 = 0


A) (y2) 24(x+2) 2=1\frac { ( y - 2 ) ^ { 2 } } { 4 } - ( x + 2 ) ^ { 2 } = 1
B) (x2) 24(y+2) 2=1\frac { ( x - 2 ) ^ { 2 } } { 4 } - ( y + 2 ) ^ { 2 } = 1
C) (y4) 24(x+4) 2=1\frac { ( y - 4 ) ^ { 2 } } { 4 } - ( x + 4 ) ^ { 2 } = 1
D) (x+2) 2(y2) 24=1( x + 2 ) ^ { 2 } - \frac { ( y - 2 ) ^ { 2 } } { 4 } = 1

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