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Solve the Equation on the Interval [0, 2π) cos2x=32\cos 2 x = \frac { \sqrt { 3 } } { 2 }

Question 178

Multiple Choice

Solve the equation on the interval [0, 2π) .
- cos2x=32\cos 2 x = \frac { \sqrt { 3 } } { 2 }


A) π12,11π12,13π12,23π12\frac { \pi } { 12 } , \frac { 11 \pi } { 12 } , \frac { 13 \pi } { 12 } , \frac { 23 \pi } { 12 }
B) π6,11π6\frac { \pi } { 6 } , \frac { 11 \pi } { 6 }
C) π2\frac { \pi } { 2 }
D) 3π2\frac { 3 \pi } { 2 }

Correct Answer:

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