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Solve the Equation on the Interval [0, 2π) sec2x2=tan2x\sec ^ { 2 } x - 2 = \tan ^ { 2 } x

Question 173

Multiple Choice

Solve the equation on the interval [0, 2π) .
- sec2x2=tan2x\sec ^ { 2 } x - 2 = \tan ^ { 2 } x


A) no solution
B) π6\frac { \pi } { 6 }
C) π4\frac { \pi } { 4 }
D) π3\frac { \pi } { 3 }

Correct Answer:

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