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The Model Predicted  distance =3.30+0.235× speed \sqrt { \text { distance } } = 3.30 + 0.235 \times \text { speed }

Question 20

Multiple Choice

The model predicted  distance =3.30+0.235× speed \sqrt { \text { distance } } = 3.30 + 0.235 \times \text { speed } can be used to predict the
Stopping distance (in feet) for a car traveling at a specific speed (in mph) . According to
This model, about how much distance will a car going 65 mph need to stop?


A) 345.0 feet
B) 18.6 feet
C) 27.0 feet
D) 4.3 feet
E) 729.0 feet

Correct Answer:

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