SCENARIO 11-11
An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants all 3
varieties of the seeds on each of 5 different patches of fields. She then measures the crop yield in
bushels per acre. Treating this as a randomized block design, the results are presented in the table that
follows.

\begin{array}{rrrr}\underline {\text { Fields }} &\underline {\text { Smith}}& \underline{\text {Walsh}}& \underline{\text {Trevor }}\\1&11.1 & 19.0 & 14.6 \\2&13.5 & 18.0 & 15.7 \\3&15.3 & 19.8 & 16.8 \\4&14.6 & 19.6 & 16.7 \\5&9.8 & 16.6 & 15.2\end{array}

-Referring to Scenario 11-11, the null hypothesis for the randomized block F test for the difference in the means is a)

H _ { 0 } : \mu _ { \text {.Field } 1 } = \mu _ { \text {.Field } 2 } = \mu _ { \text {.Field } 3 } = \mu _ { \text {.Field } 4 } = \mu _ { \text {.Field } 5 }

H _ { 0 } : \mu _ { \text {.Smith } } = \mu _ { \text {.Walsh } } = \mu _ { \text {.Trevor } }

H _ { 0 } : M _ { \text {.Field 1 } } = M _ { \text {.Field } 2 } = M _ { \text {.Field } 3 } = M _ { \text {.Field } 4 } = M _ { \text {.Field } 5 }

\quad H _ { 0 } : M _ { \text {.Smith } } = M _ { \text {.Walsh } } = M _ { \text {.Trevor } }

SCENARIO 6-8 A Company Has 125 Personal Computers. the Probability That Any

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