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SCENARIO 11-11
an Agronomist Wants to Compare the Crop Yield

Question 47

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SCENARIO 11-11
An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants all 3
varieties of the seeds on each of 5 different patches of fields. She then measures the crop yield in
bushels per acre. Treating this as a randomized block design, the results are presented in the table that
follows.  Fields  SmithWalshTrevor 111.119.014.6213.518.015.7315.319.816.8414.619.616.759.816.615.2\begin{array}{rrrr}\underline {\text { Fields }} &\underline {\text { Smith}}& \underline{\text {Walsh}}& \underline{\text {Trevor }}\\1&11.1 & 19.0 & 14.6 \\2&13.5 & 18.0 & 15.7 \\3&15.3 & 19.8 & 16.8 \\4&14.6 & 19.6 & 16.7 \\5&9.8 & 16.6 & 15.2\end{array}
-Referring to Scenario 11-11, the null hypothesis for the randomized block F test for the difference in the means is a) H0:μ.Field 1=μ.Field 2=μ.Field 3=μ.Field 4=μ.Field 5H _ { 0 } : \mu _ { \text {.Field } 1 } = \mu _ { \text {.Field } 2 } = \mu _ { \text {.Field } 3 } = \mu _ { \text {.Field } 4 } = \mu _ { \text {.Field } 5 }
b) H0:μ.Smith =μ.Walsh =μ.Trevor H _ { 0 } : \mu _ { \text {.Smith } } = \mu _ { \text {.Walsh } } = \mu _ { \text {.Trevor } }
c) H0:M.Field 1 =M.Field 2=M.Field 3=M.Field 4=M.Field 5H _ { 0 } : M _ { \text {.Field 1 } } = M _ { \text {.Field } 2 } = M _ { \text {.Field } 3 } = M _ { \text {.Field } 4 } = M _ { \text {.Field } 5 }
d) H0:M.Smith =M.Walsh =M.Trevor \quad H _ { 0 } : M _ { \text {.Smith } } = M _ { \text {.Walsh } } = M _ { \text {.Trevor } }

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