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Solve the Problem λ\lambda = 33 Construct a Probability Table for the Random Variable
X

Question 125

Multiple Choice

Solve the problem.
-A naturalist leads whale watch trips every morning in March. The number of whales seen X, has a Poisson distribution with parameter λ\lambda = 3.3. Construct a probability table for the random variable
X. Compute the probabilities for 0 - 5 sightings.


A)
xP(X=x) 00.03710.12220.20130.22140.18250.012\begin{array}{c|c}\mathrm{x} & \mathrm{P}(\mathrm{X}=\mathrm{x}) \\\hline 0 & 0.037 \\1 & 0.122 \\2 & 0.201 \\3 & 0.221 \\4 & 0.182 \\5 & 0.012\end{array}

B)
xP(X=x) 00.03710.12220.20130.22140.18250.120\begin{array}{c|c}\mathrm{x} & \mathrm{P}(\mathrm{X}=\mathrm{x}) \\\hline 0 & 0.037 \\1 & 0.122 \\2 & 0.201 \\3 & 0.221 \\4 & 0.182 \\5 & 0.120\end{array}

C)
xP(X=x) 00.03710.12220.02130.22140.18250.120\begin{array}{c|c}\mathrm{x} & \mathrm{P}(\mathrm{X}=\mathrm{x}) \\\hline 0 & 0.037 \\1 & 0.122 \\2 & 0.021 \\3 & 0.221 \\4 & 0.182 \\5 & 0.120\end{array}

D)
xP(X=x) 00.37010.12220.20130.22140.18250.120\begin{array}{c|c}\mathrm{x} & \mathrm{P}(\mathrm{X}=\mathrm{x}) \\\hline 0 & 0.370 \\1 & 0.122 \\2 & 0.201 \\3 & 0.221 \\4 & 0.182 \\5 & 0.120\end{array}

Correct Answer:

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