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Solve the Equation sinθ=32\sin \theta = \frac { \sqrt { 3 } } { 2 }

Question 6

Multiple Choice

Solve the equation. Give a general formula for all the solutions.
- sinθ=32\sin \theta = \frac { \sqrt { 3 } } { 2 }


A) θ=π6+2kπ,θ=5π6+2kπ\theta = \frac { \pi } { 6 } + 2 k \pi , \theta = \frac { 5 \pi } { 6 } + 2 k \pi
B) θ=π6+kπ,θ=5π6+kπ\theta = \frac { \pi } { 6 } + \mathrm { k } \pi , \theta = \frac { 5 \pi } { 6 } + \mathrm { k } \pi
C) θ=π3+2kπ,θ=2π3+2kπ\theta = \frac { \pi } { 3 } + 2 k \pi , \theta = \frac { 2 \pi } { 3 } + 2 k \pi
D) θ=π3+kπ,θ=2π3+kπ\theta = \frac { \pi } { 3 } + \mathrm { k } \pi , \theta = \frac { 2 \pi } { 3 } + \mathrm { k } \pi

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