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Solve the Equation cos(2θ)=22\cos ( 2 \theta ) = \frac { \sqrt { 2 } } { 2 }

Question 101

Multiple Choice

Solve the equation. Give a general formula for all the solutions.
- cos(2θ) =22\cos ( 2 \theta ) = \frac { \sqrt { 2 } } { 2 }


A) θ=π8+2kπ,θ=7π8+2kπ\theta = \frac { \pi } { 8 } + 2 \mathrm { k } \pi , \theta = \frac { 7 \pi } { 8 } + 2 \mathrm { k } \pi
B) θ=2π3+kπ,θ=4π3+kπ\theta = \frac { 2 \pi } { 3 } + \mathrm { k } \pi , \theta = \frac { 4 \pi } { 3 } + \mathrm { k } \pi
C) θ=π4+kπ,θ=3π4+kπ\theta = \frac { \pi } { 4 } + \mathrm { k } \pi , \theta = \frac { 3 \pi } { 4 } + \mathrm { k } \pi
D) θ=π8+kπ,θ=7π8+kπ\theta = \frac { \pi } { 8 } + \mathrm { k } \pi , \theta = \frac { 7 \pi } { 8 } + \mathrm { k } \pi

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