Solve the Problem $$d = D \tan \left[ \frac { \pi } { 2 } \left( 1 - \frac { 2 M } { S } \right) \right]$$

Short Answer

Solve the problem.
-The ground movement of an earthquake near a fault line is modeled by the equation $$d = D \tan \left[ \frac { \pi } { 2 } \left( 1 - \frac { 2 M } { S } \right) \right]$$ where M is the horizontal movement (in meters) at a distance d (in kilometers) from the earthquake, D is the depth (also
in kilometers) below the surface of the center of the earthquake, and S is the total horizontal displacement (also in
meters) at the fault line. What is the horizontal movement 5 kilometers from an earthquake centered 3 kilometers below
the surface with a total horizontal displacement of 4 meters? Round the answer to the nearest 0.01 meter.