Solve the Problem $$t = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }$$

Multiple Choice

Solve the problem.
-If friction is ignored, the time t (in seconds) required for a block to slide down an inclined plane is given by the formula $$t = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }$$
where $a$ is the length (in feet) of the base and $g \approx 32$ feet per second per second is the acceleration of gravity. How long does it take a block to slide down an inclined plane with base $a = 14$ when $\theta = 45 ^ { \circ }$ ? If necessary, round the answer to the nearest tenth of a second.

A) $1.3 \mathrm { sec }$
B) $0.3 \mathrm { sec }$
C) $1.4 \mathrm { sec }$
D) $1.1 \mathrm { sec }$