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Graph the Function Using Its Vertex, Axis of Symmetry, and Intercepts

Question 27

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Graph the function using its vertex, axis of symmetry, and intercepts.
- f(x) =x2+12xf(x) =x^{2}+12 x
 Graph the function using its vertex, axis of symmetry, and intercepts. - f(x) =x^{2}+12 x     A)  vertex   (-6,36)    intercept   (0,72)       B)   \begin{array}{l} \text { vertex }(6,36)  \\ \text { intercept }(0,72)  \end{array}      C)  \begin{array}{l} \text { vertex }(6,-36)  \\ \text { intercepts }(0,0) ,(12,0)  \end{array}     D)  \begin{array}{l} \text { vertex }(-6,-36)  \\ \text { intercepts }(0,0) ,(-12,0)  \end{array}
A) vertex (6,36) (-6,36)
intercept (0,72) (0,72)
 Graph the function using its vertex, axis of symmetry, and intercepts. - f(x) =x^{2}+12 x     A)  vertex   (-6,36)    intercept   (0,72)       B)   \begin{array}{l} \text { vertex }(6,36)  \\ \text { intercept }(0,72)  \end{array}      C)  \begin{array}{l} \text { vertex }(6,-36)  \\ \text { intercepts }(0,0) ,(12,0)  \end{array}     D)  \begin{array}{l} \text { vertex }(-6,-36)  \\ \text { intercepts }(0,0) ,(-12,0)  \end{array}

B)  vertex (6,36)  intercept (0,72) \begin{array}{l}\text { vertex }(6,36) \\\text { intercept }(0,72) \end{array}

 Graph the function using its vertex, axis of symmetry, and intercepts. - f(x) =x^{2}+12 x     A)  vertex   (-6,36)    intercept   (0,72)       B)   \begin{array}{l} \text { vertex }(6,36)  \\ \text { intercept }(0,72)  \end{array}      C)  \begin{array}{l} \text { vertex }(6,-36)  \\ \text { intercepts }(0,0) ,(12,0)  \end{array}     D)  \begin{array}{l} \text { vertex }(-6,-36)  \\ \text { intercepts }(0,0) ,(-12,0)  \end{array}

C)  vertex (6,36)  intercepts (0,0) ,(12,0) \begin{array}{l}\text { vertex }(6,-36) \\\text { intercepts }(0,0) ,(12,0) \end{array}
 Graph the function using its vertex, axis of symmetry, and intercepts. - f(x) =x^{2}+12 x     A)  vertex   (-6,36)    intercept   (0,72)       B)   \begin{array}{l} \text { vertex }(6,36)  \\ \text { intercept }(0,72)  \end{array}      C)  \begin{array}{l} \text { vertex }(6,-36)  \\ \text { intercepts }(0,0) ,(12,0)  \end{array}     D)  \begin{array}{l} \text { vertex }(-6,-36)  \\ \text { intercepts }(0,0) ,(-12,0)  \end{array}

D)  vertex (6,36)  intercepts (0,0) ,(12,0) \begin{array}{l}\text { vertex }(-6,-36) \\\text { intercepts }(0,0) ,(-12,0) \end{array}
 Graph the function using its vertex, axis of symmetry, and intercepts. - f(x) =x^{2}+12 x     A)  vertex   (-6,36)    intercept   (0,72)       B)   \begin{array}{l} \text { vertex }(6,36)  \\ \text { intercept }(0,72)  \end{array}      C)  \begin{array}{l} \text { vertex }(6,-36)  \\ \text { intercepts }(0,0) ,(12,0)  \end{array}     D)  \begin{array}{l} \text { vertex }(-6,-36)  \\ \text { intercepts }(0,0) ,(-12,0)  \end{array}







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