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Solve For a.(a>0)a . ( a > 0 ) a2+b2+c2=d2a ^ { 2 } + b ^ { 2 } + c ^ { 2 } = d ^ { 2 }

Question 45

Multiple Choice

Solve for a.(a>0) a . ( a > 0 )
a2+b2+c2=d2a ^ { 2 } + b ^ { 2 } + c ^ { 2 } = d ^ { 2 }


A) a=±d2b2c2a = \pm \sqrt { d ^ { 2 } - b ^ { 2 } - c ^ { 2 } }
B) a=d2b2c2a = \sqrt { d ^ { 2 } - b ^ { 2 } - c ^ { 2 } }
C) a=dbca = d - b - c
D) a=±(dbc) a = \pm ( d - b - c )

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