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When a Stationary Plutonium-239 94239Pu{ } _ { 94 } ^ { 239 } \mathrm { Pu }

Question 89

Multiple Choice

When a stationary plutonium-239, 94239Pu{ } _ { 94 } ^ { 239 } \mathrm { Pu } , decays into uranium-235 plus an alpha particle, the energy released in the process is 5.24MeV5.24 \mathrm { MeV } . The following masses are known:
24He:4.002603u{ } _ { 2 } ^ { 4 } \mathrm { He } : \quad 4.002603 \mathrm { u }
92235U:235.043924u{ } _ { 92 } ^ { 235 } \mathrm { U } : \quad 235.043924 \mathrm { u }
What is the mass of the 94239Pu{ } _ { 94 } ^ { 239 } \mathrm { Pu } nucleus, in amu? (1u=931.494MeV/c2) \left( 1 \mathrm { u } = 931.494 \mathrm { MeV } / \mathrm { c } ^ { 2 } \right)


A) 239.00189u239.00189 \mathrm { u }
B) 239.02775u239.02775 \mathrm { u }
C) 238.98884u238.98884 \mathrm { u }
D) 239.05215u239.05215 \mathrm { u }
E) 238.99919u238.99919 \mathrm { u }

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